Pick all that apply

• 1Choice 1.

  The semantics are copy-in copy-out: the value is copied in at the call and written back to the original variable when the function returns (the compiler may pass a direct reference as an optimization)

• 2Choice 2.

  Capturing an inout parameter inside an escaping closure is a compile error

• 3Choice 3.

  Passing the same variable to two inout arguments at once (swap(&a, &a)) violates exclusive memory access and produces a compile error or a runtime trap

• 4Choice 4.

  inout is pass by reference, so it's exactly the same as changing the parameter type to a class

• 5Choice 5.

  A computed property (one with a getter and setter) can also be passed as an inout argument with &prop